AxC, début de statistique

[elf]

Statistique

Un début de statistique pour le CLT, pour avoir plus de précision il faudrait avoir export de la base de données et automatiser, ou (bcp) de volontaires.

Ce n'est pas:
- une étude de l'arbre complet
- une étude de chaque cas dans le détail
- un débat savoir si il faut ou pas, ou avec X conditions etc...

... c'est juste quelques données brutes.

AxC (32) dans la base de données: ordre alphabétique de "A New Evoluton ---Pacino---" à "Alf Mot'ovský dvor CS" (1000 chiens), + qq autres mariages croisés. Seuls les mariages ayant dans la descendance au moins un résultat sont relevés.

Résultats

AxC: ==> résultats inconnus = 169 | A = 45 | B = 11 | C = 17 | D = 12 | E = 6

A+B = 56 (sur 91) = 61.5% des resultats connus
C+D+E = 35 (sur 91) = 38.5% des resultats connus

A+B = 56 (sur 260) = 21.5% de l'ensemble
C+D+E = 35 (sur 260) = 13.5% de l'ensemble

Détails

Abe z Molu CS : C(2/0)
Bessy z Kladenské záøe CS : A1
==> descendance : ? = 3 | A = 3 [3xA(0/0)]

Abe z Molu CS : C(2/0)
Alma z Fialkova : A(0/0)
==> descendance : ? = 16 | A = 4 [4xA(0/0)] | C = 1 [1xC(2/2)] | D = 1 [1xD(3/2)]

Afra Crying Wolf: C
Borko Kollárov dvor: A(0/0)
==> descendance : ? = 1 | A = 1 [1xA]

Agar Morusovy haj: C(0/2)
Nancy sedá eminence : A(0/0)
==> descendance : ? = 1 | A = 2 [2xA(0/0)] | C = 1 [1xC]

Elsa z Molu CS: C(1/2)
Colt Zepeø CS: A(0/0)
==> descendance : ? = 6 | E = 1 [1xE(4/2)]

Bryta z Dolních Marsovic CS: C(1/2)
Agar Reolup: A(0/0)
==> descendance : ? = 2 | E = 1 [1xE(4/4)]

Alba Chlumecké podzámèí: C(2/2)
Gaj Jimili CS: A(0/0)
==> descendance : ? = 5 | A = 1 [A2] | B = 1 [1xB(1/1)]

Alexa De-To: C(2/2)
Brix Ekar CS: A(0/0)
==> descendance : ? = 10 | B = 1 | E = 1 [1xE(4/4)]

Alexa z Porèova mlýna: C(2/2)
Gaj Jimili CS: A(0/0)
==> descendance : ? = 3 | A = 1 [1xA(0/0)] | C = 1 [1xC(2/2)]

Alexa z Porèova mlýna: C(2/2)
Milo Ruskov dvor CS: A(0/0)
==> descendance : ? = 3 | B = 1 [1xB(0/1)] | C = 2 [2xC(2/2)]

Alexa z Porèova mlýna: C(2/2)
Dak Kollárov dvor: A(0/0)
==> descendance : ? = 2 | A = 2 [2xA(0/0)] | C = 1 [1xC(2/2)]

Arnie z Kamenaèek: C(1/2)
Bazilisek Stín vlka: A(0/0)
==> descendance : ? = 8 | A = 2 [1xA(0/0)]

-------

Dolores Eden severu : C(1/2)
Bony z Mìsta Sadské : A(0/0)
==> descendance : ? = 8 | A = 2 [2xA(0/0)] | B = 1 [1xB(1/1)] | C = 2 [1xC(2/2), 1xC(2/1)]

Durcás Dorka Fehérlófia : C
Cord sedá eminence : A(0/0)
==> descendance : ? = 5 | C = 2 [2xC]

Hagga Kollárov dvor: C(0/2)
Argos Mrazivé ticho: A(0/0)
==> descendance : ? = 1 | A = 1 [1xA(0/0)] | B = 1 [1xB(1/0)] | D = 1 [1xD(3/0)] | E = 1 [1xE(4/3)]

Bety Zepeø CS: C(2/2)
Amur z Ïáblova kaòonu CS: A(0/0)
==> descendance : ? = 7 | A = 4 [4xA(0/0)] | D = 1 [1xD(3/3)]

Canis z Molu CS: C(0/2)
Ikar z Krotkovského dvora CS: A(0/0)
==> descendance : ? = 5 | A = 3 [3xA(0/0)] | D = 2 [2xD(3/3)]

Canis z Molu CS: C(0/2)
Ariel Dar pøírody CS: A(0/0)
==> descendance : ? = 12 | D = 1 [1xD(3/2)]

Hanka sedá eminence: C(2/0)
Ares od surdy: A(0/0)
==> descendance : ? = 5 | A = 1 [1xA(0/0)] | C = 1 [1xC(2/2] | E = 1 [1xE(4/4)]

Baghira Zelený paprsek: C(2/2)
Dick Chlumecké podzámèí: A(0/0)
==> descendance : ? = 7 | E = 1 [1xE(4/4)]

Brenna sedý chlup: C
Dak Kollárov dvor: A(0/0)
==> descendance : ? = 2 | A = 5 [2xA, 3xA(0/0)] | B = 1 [1xB(1/1)]

Betty z Uher: C(2/2)
Brix z Porèova mlýna: A
==> descendance : ? = 5 | A = 1 [1xA(0/0)] | B = 1 [1xB(1/0)] | C = 2 [1xC(2/1), 1xC(2/0)] | D = 1 [1xD(3/2)]

Betty z Uher: C(2/2)
Gero Kollárov dvor: A(0/0)
==> descendance : ? = 4 | A = 1 [1xA(0/0)] | D = 1 [1xD(3/2)]

Hena Kysucká hviezda: C(2/2)
Bony z Mìsta Sadské: A(0/0)
==> descendance : ? = 4 | B = 1 [1xB(1/0)] | C = 1 [1xC(2/1)]

Hena Kysucká hviezda: C(2/2)
Kairo od Uhoste: A(0/0)
==> descendance : ? = 7 | A = 4 [4xA(0/0)] | B = 1 [1xB(1/1)]

Dia Dakmat: C(2/1)
Grey Wolf z Molu Es: A(0/0)
==> descendance : ? = 5 | A = 1 [1xA(0/0)]

Dia Dakmat: C(2/1)
Jerry Lee z Molu Es: A(0/0)
==> descendance : ? = 1 | A = 3 [3xA(0/0)] | B = 1 [1xB] | C = 1 [1xC(1/2] | D = 2 [1xD(3/0), 1xD(3/3)]

Dia Dakmat: C(2/1)
Dat sedý chlup: A
==> descendance : ? = 3 | A = 1 [1xA(0/0)]

Bad Vlèí nadìje: C(2/2)
Dixie Dakmat: A(0/0)
==> descendance : ? = 10 | C = 1 [1xC(2/2] | D = 1 [1xD(3/2)]

Britt z Molu CS: C(2/1)
Foma sedá eminence: A(0/0)
==> descendance : ? = 5 | C = 1 [1xC(2/0] | D = 1 [1xD(3/3)]

Beky sedý samotáø: C(2/1)
Atewa Bílý mìsíc: A
==> descendance : ? = 6 | B = 1 [1xB(1/1)]

Beky sedý samotáø: C(2/1)
Good Boy z Molu Es: A(0/0)
==> descendance : ? = 6 | A = 2 [1xA(0/0)]